Wednesday, April 1, 2020

Speed of a boat math problem?

Jackelyn Archut: Tad

Rhett Kaines: Let the south bound boat travel at x mphEast bound boat = ( x+3) mphIn 2 hours distance traveled by them will be 2x and 2( x+3) milesUSE PYTHAGORAS THEOREM( 2x) ^2 + ( 2x+6)^2 = 30^24x^2 + 4x^2 + 36 + 24x = 9008x^2 +24x - 864 = 0x^2 + 3x - 108 = 0( x +12) ( x-9) = 0x = 9ANSWER 9mph CHECK2X9 = 182 X 12 = 2418^2 +24^2 = 324+ 576 = 900/900 = 30 miles...Show more

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